leetcode::power_of_two

Struct Solution

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pub struct Solution;

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impl Solution

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pub fn is_power_of_two(n: i32) -> bool

2 的幂：大于 0，而且二进制表示中只有一个 1。

n > 0 时才有可能是 2 的幂 n & (n - 1) 相当于把最后一位的 1 变成 0，如果结果为 0 那就是 2 的幂，否则不是。

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